Hmm. Ok I think I got how it worked. A simple sketch would be useful next time.
What you are doing here as it seems is transport electrons from a “lower magnetic potential” (don’t know the real phrase for that) to a “higher magnetic potential”. Timing the “release” of those electrons might increase efficiency as the force vector is then in line with the direction you want to go. Although I don’t think it’s really needed, rotation of the whole device may be sufficient.
Also I don’t see why you need to “discharge” and “charge” the capacitors? It looks like they flow from one capacitor to the other and in a theoretical device wouldn’t escape to anywhere. Especially as whatever you use as a conductor has free electrons naturally.
Lets say the neutral position of the rod is orthogonal to the stationary magnet. The free electrons in the conductor stay where they are. You turn the rod. Electrons start to move and accumulate on the “faar” capacitor. You turn the rod. It does it the other way around.
Add a switch (as you did), to trap the electrons in the far capacitor, when you bring the “full” capacitor to the front again there will be more electrons to push back then in the “start rotation”. It also makes movements more “sharp” Although it will happen in the rod anyway, but most of the capacitance is inside the capacitors, so that isn’t a problem.
What I’m not sure about yet is if there would really be Voltage between the two capacitors in the “inline” situation. Usually voltage is created by continual changing magnetic fields or movement trough such fields, although in a small enough time frame you may be able to use that voltage before it discharges. Probably does work.
O wait:
Electrons start to move and accumulate on the “faar” capacitor.
In turn depriving the capacitor near the magnet of electrons. This creates a voltage contradicting the force you created, forcing the electrons back to the “front”. Deepening how big the two forces are and considering that the Voltage will rise in an e-function, there will be a point of equilibrium. So in itself not really a deal breaker, but something you need to factor in
The whole charging discharging isn’t really needed. It happens in the rod anyway due to the Voltage described above.
Concerning your request for solutions:
I don’t see a way around the counter force created by the deprivation of the conductor as it is applied instantly. You could scale up the magnet, thus pushing the point of equilibrium further “down”, moving the electrons further, getting more momentum out of the system.
O wait … again:
Did you factor in the force created by the unequal weighed rod? After all. You move those electrons back up. I don’t think it really matter if it happens by magnetic applied force/voltage or by physically moving the capacitor.
I don’t want to discredit your idea. But the problems I see are very much like the things in perpetuum mobiles:
Where gravity is the magnetic field.
I know you use a motor to push energy in. But as I see it, all the energy is transformed to heat when the electrons travel the rod.
Ok. Let’s try to comprehend where the energy goes. We have a motor that has power and provides energy as needed.
- 1
- |
- |
- o M (Magnet)
- |
- |
- 2
- The rod is in its neutral position (orthogonal to the pole of the magnet). Capacitor 1 and 2 are electrically connected.
- The motor rotates the rod clockwise.
- Electrons are forced into capacitor 2. A voltage across capacitor 1 and 2 emerges. Energy was needed to move the electrons out of their Natural Equilibrium. Let’s call that Energy-A1
- Capacitor 1 reaches the magnet. Capacitor 1 and 2 is electrically disconnected.
- The motor now moves capacitor 2 towards the magnet. It has to push the electrons into the Magnetic field. This requires energy: Energy-B1
- Capacitor 2 reaches the magnet. Capacitors are connected. Energy-A1 and Energy-B1 are released.
- The electrons and the ship is being accelerated and rush away from each other. The Energy in their movement is called Energy-C1
- The deprivation of electrons in Capacitor 2 and abundance in Capacitor 1 create an electric field (Voltage). (correct me if I talk mumbo jumbo)
- The electric field overcomes the magnetic field and decelerates the electrons and the ship.
As you may be able to see. Energy-A never leaves the system. Due to losses it may be needed to “fill it up again” but in essence it stays and feeds back into itself. It’s “blind” useless Energy movement.
What’s interesting is Energy-B. It looks like it may be possible to build up that energy.
You may be able to keep the kinetic energy transferred of the ship if you stop the electrons from being affected by the electric field in the right time. Disconnecting the connection between C1 and C2 before Energy-B is completely converted into “Voltage” (chrarge? what’s the potential energy of the electric field again?).
But I think in the end the Kinetic energy of both, the ship and the electrons are transferred back into something else. Because the electrons will run into the capacitor … and the capacitor won’t budge, electric field will build up and stop them and thus the ship.
Just my steps trying to comprehend your idea. Make of it what you want. Also sorry for not using the most correct therms. I know most of the principles but don’t get the wording right most of the time.